Sodium propionate on reaction with sodalime gives :

C_{2} H_{6}

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N a_{2} C O_{3}

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both A and B

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none of the above

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Solution

The correct option is A both A and B
$C H_{3} C H_{2} C O O N a + N a O H C a O - - \to Δ C_{2} H_{6} + N a_{2} C O_{3}$
The given reaction is decarboxylation reaction used to prepare alkane from sodium salt of higher fatty acid in presence of calcium oxide as a product.

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