Question

Sodium salt of benzoic acid on heating with sodalime gives a hydrocarbon '$A$' along with sodium carbonate. The compound '$A$' on treatment with excess of chlorine in the presence of anhydrous $AlC{l}_3$ will give

• A. Hexachlorobenzene
• B. Hexachlorocyclohexane
• C. $2,4,6-$Trichlorophenol
• D. $1,4-$Dichlorobenzene

Answer 1

The correct option is A Hexachlorobenzene

Sodium salt of benzoic acid on heating with sodalime gives a hydrocarbon benzene along with sodium carbonate. Benzene on treatment with excess of chlorine in the presence of anhydrous $AlC{l}_3$ will give hexachlorobenzene.