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Shape and Geometry Using VSEPR

Sodium supero...

Question

Sodium superoxides $N a O_{2}$ can't be prepared directly from sodium, but form $N a_{2} O_{2}$ ,Then the amount of $N a_{2} O_{2}$ required to prepare 11 g of $N a O_{2}$ is :

7.2 g

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7.8 g

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3.6 g

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3.9 g

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Solution

The correct option is B 7.8 g
$N a_{2} O_{2} + O_{2} \to 2 N a O_{2}$ .
So 78 grams of $N a_{2} O_{2}$ gave 110 grams of $2 N a O_{2}$
How many grams would give 11grams of $2 N a O_{2}$ ?
$78 \times 11 = 110 \times x$

$\frac{78 \times 11}{110}$ = $7.8$
So 7.8 grams is required.
Hence option B is correct.

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