Question

Soft drink A has water to lime ratio of 3 : 5 while soft drink B has 4 : 6. Find the drink which has less percentage of lime and what is the difference in percentage?

• A. A < B by 2.5%
• B. A > B by 3.5%
• C. A < B by 3.5%
• D. A > B by 2.5%

Answer 1

The correct option is D A > B by 2.5%

In soft drink A
Ratio of water to lime = 3 : 5
total ratio = 3 + 5 = 8

percentage of lime
$=\frac{5}{8}\times 100=62.5\text{\%}$

In soft drink B
Ratio of water to lime = 4 : 6
total ratio = 4 + 6 = 10

percentage of lime
$=\frac{6}{10}\times 100=60\text{\%}$

So, soft drink B has less concentration of lime by
= 62.5 - 60 = 2.5%