Question

Soham poured some water in two fish bowls. He poured $4\frac{5}{8}$ liters of water in the first dish bowl and $2\frac{5}{6}$ liters in the second bowl. How much water Soham pour in the first bowls altogether?

Answer 1

In first bowl he poured = $4\frac{5}{8}l$

$=\frac{37}{8}l.$

In second bowl $=2\frac{5}{6}l$

$=\frac{17}{6}l$

altogether he bowled $=\frac{37}{8}+\frac{7}{6}$

$=\frac{111+68}{24}$

$=\frac{179}{24}=7\frac{11}{24}l$