Sohan soaked 2 g raisins each of exactly equal mass in three beakers A, B and C each
containing same amount of tap water at the room temperature. After 30 minutes he
removed raisins from beaker A after 60 minutes from beaker B and after 90 minutes
from beaker C He calculated the percentage absorption of water in each case. If $P_{A}, P_{B}$
and $P_{C}$ denote percentage absorption, then on the basis of observation made by Sohan,
the correct representation of the conclusion should be :

P_{A} > P_{B} > P_{C}

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P_{A} = P_{B} = P_{C}

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P_{A} < P_{B} < P_{C}

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P_{A} < P_{C} > P_{B}

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Solution

The correct option is C $P_{A} < P_{B} < P_{C}$
C. Pa <Pb<Pc
Solution : As we know due to endosmosis the water moves into the cells of the raisins when placed in water. The raisins that are present in the water for the longest time will also absorb the highest and weigh the highest.
So the correct answer is "Pa <Pb<Pc".

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