Question

Solar insolation of a rectangular module $(1.5\text{m}\times 2.0\text{m})$ of a solar cell is $550{\text{W/m}}^2.$ If efficiency of the cell is $12\%$, what power can be drawn from cell?

• A. $396\text{W}$
• B. $240\text{W}$
• C. $99\text{W}$
• D. $198\text{W}$

Answer 1

The correct option is D $198\text{W}$

Given:
$\text{SI}=550{\text{W/m}}^2;\eta =12\%$
$A=1.5\times 2=3{\text{m}}^2$

So, the efficiency of cell,

$\eta =\frac{P_{\text{out}}}{P_{\text{in}}}\times 100..........\left(1\right)$

We know, $\text{SI}=\frac{P_{\text{in}}}{\text{Area}}\Rightarrow P_{\text{in}}=\text{SI}\times \text{Area}$

$\therefore P_{\text{in}}=(550\times 3)\text{W}..........\left(2\right)$

From eqns. $\left(1\right)$ & $\left(2\right)$,

$P_{\text{out}}=\frac{\eta }{100}\times P_{\text{in}}$

$=\frac{12}{100}\times 550\times 3$

$\therefore P_{\text{out}}=198\text{W}$

Therefore, option $\left(\text{D}\right)$ is the right choice.