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Question

Solid ammonium carbamate dissociates to give ammonia and carbon dioxide as follows:
NH2COONH4(s)2NH3(g)+CO2(g)
At equilibrium, ammonia is added such that partial pressures of NH3 now equals the original total pressure. Calculate the ratio of the total pressures now to the original total pressure.

A
3127
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B
6040
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C
319
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D
6227
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Solution

The correct option is A 3127
NH2COONH4(s)2NH3(g)+CO2(g)
Initial 2P P
KP=(PNH3)2(PCO2)
KP=(2P)2(P) ......(i)
PT(initial)=3P
NH2COONH4(s)2NH3(g)+CO2(g)
Final 3P P
Kp=(3P)2(P) ......(ii)
From eq. (i) and (ii)
(2P)2(P)=(3P)2(P)
P=4P9
PT(New)PT(Old)=3P+P3P=3P+4P93P=3127.

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