Solid sodium amide, $N a N H_{2}$ has a cubic closed packed arrangement of $N H_{2}^{-}$ ions with _____ voids occupied by $N a^{+}$ ions.

half the number of octahedral

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all tetrahedral

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half the number of tetrahedral

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double the number of octahedral

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Solution

The correct option is A half the number of tetrahedral
$Z_{e f f e c t i v e} o f {N H_{2}}^{-} = 6 \times \frac{1}{2} + 8 \times \frac{1}{8} = 4$ (CCP arrangement)

To maintain the $N a N H_{2}$ formula $Z_{e f f e c t i v e}$ of $N a^{+}$ must be $4$ .
So, $N a^{+}$ will be present at alternate tetrahedral voids.

$Z_{e f f e c t i v e}$ of $N a^{+} = \frac{1}{2} \times 8 = 4$

Answer: (C) half the number of tetrahedral

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Solid sodium amide, NaNH2 has a cubic closed packed arrangement of NH−2 ions with _____ voids occupied by Na+ ions.

The correct option is A half the number of tetrahedralZeffectiveofNH2−=6×12+8×18=4 (CCP arrangement)To maintain the NaNH2 formula Zeffective of Na+ must be 4.So, Na+ will be present at alternate tetrahedral voids.Zeffective of Na+=12×8=4Answer: (C) half the number of tetrahedral

Solid sodium amide, $N a N H_{2}$ has a cubic closed packed arrangement of $N H_{2}^{-}$ ions with _____ voids occupied by $N a^{+}$ ions.