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Byju's Answer
Standard XII
Chemistry
Common Ion Effect
Solubility of...
Question
Solubility of
H
g
2
C
l
2
in water is
S
mol
l
i
t
r
e
−
1
. The
K
s
p
of
H
g
2
C
l
2
is:
A
16
S
4
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B
4
S
3
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C
64
S
4
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D
16
S
2
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Solution
The correct option is
B
4
S
3
H
g
2
C
l
2
→
H
g
2
+
2
+
2
C
l
−
S
2
S
k
s
p
=
[
H
g
2
+
2
]
×
[
C
l
−
]
=
(
S
)
(
2
S
)
2
=
4
S
3
Hence, option B is correct.
Suggest Corrections
0
Similar questions
Q.
Solubility of
H
g
2
C
l
2
in water is
S
mol^4
l
i
t
r
e
−
1
. The
K
s
p
of
H
g
2
C
l
2
is
Q.
Solubility of the
H
g
2
C
l
2
in a solvent is
S
moles/litre. Its solubility product will be:
Q.
Assertion :
P
b
C
l
2
and
H
g
2
C
l
2
precipitates can be separated by hot water. Reason:
H
g
2
C
l
2
is blackened by
a
q
.
N
H
3
Q.
State whether the given statement is true or false:
H
g
2
C
l
2
is precipitated if
[
H
g
2
+
2
]
[
C
l
−
]
2
is greater than
K
s
p
(
H
g
2
C
l
2
)
.
Q.
P
b
C
l
2
is soluble in hot water
A
g
C
l
is soluble in
a
q
.
N
H
3
while
H
g
2
C
l
2
is blackened by
N
H
3
.
If the given statement is true enter 1 else enter 0.
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