Question

Solubility of $M{X}_2$ type electrolytes is $0.5\times {10}^{-4}mol/L$, Then find out $K_{sp}$ of electrolytes.

• A. $5\times {10}^{-12}$
• B. $25\times {10}^{-10}$
• C. $1\times {10}^{-13}$
• D. $5\times {10}^{-13}$

Answer 1

The correct option is D $5\times {10}^{-13}$

For $M{X}_2$ type of electrolyte

$M{X}_2\rightleftharpoons M^{+2}+2X^{-}$. So if the solubility is $S$ then the solubility product would be $4S^3$

Here, solubility S= $0.5\times {10}^{-4}mol/L$

So, solubility product $K_{sp}=4\times (0.5\times {10}^{-4}{)}^3$

=$5\times {10}^{-13}$ So the correct option is D