Question

Solubility of salt X in water is 32 at 30${}^o$C. Calculate the amount of solvent present in 500 g of saturated solution of X.

• A. 160 g
• B. 379 g
• C. 460 g
• D. 68 g

Answer 1

The correct option is B 379 g

The solubility of the salt at ${30}^{o}C$ is $32$. Amount of saturated solution of the salt present is $500g$.

Let the amount of solute, or salt $X$ present in the saturated solution be $x$ grams.

The amount of solvent present in the saturated solution is $(500-x)$ grams.

Thus, solubility of the salt $X$ is given by the formula -

Solubility $=$$\frac{x}{500-x}\times$$100$, where $x$ is the amount of solute. And $(500-x)$ is the amount of solvent.

Putting the value of solubility in the above mentioned equation, we get,

$32$ $=$ $\frac{x}{500-x}\times$$100$

Or, $16000-32x$ $=$ $100x$

Or, $132x$ $=$ $16000$

Or, $x$ $=$ $121$

Thus, amount of salt $X$ present in the saturated solution is $121g$.

Thus, the amount of solvent present in the solution is $(500-121)$, that is $379g$.