Solubility of sodium chloride solution at room temperature is $36 g / 100 g$ of water. $200 g$ of saturated solution of Sodium chloride was allowed to evaporate when $75 g$ of water evaporated. Calculate the amount of crystals deposited due to evaporation.

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Solution

Weight of saturated solution of $NaCl$ = $200 g$
Weight of saturated solution containing $36 g$ of $NaCl$ at room temperature
$100 + 36 = 136 g$
$200 g$ of saturated solution contains crystal= $\frac{36}{136} \times 200$
= $52.94 g$
Amount of water in $200 g$ of saturated solution= $200 - 52.94$
= $147.06 g$
Water left after evaporation of $75 g$ of water= $147.06 - 75.0$
= $72.06 g$
Amount of $NaCl$ crystals in $147.06 g$ of water= $52.94 g$
Amount of $NaCl$ crystals in $72.06 g$ of water = $\frac{52.94}{147.07} \times 72.06$
= $25.94 g$
Amount of $NaCl$ crystals deposited due to evaporation= $52.94 - 25.94$
= $27 g$
$27 g$ of $NaCl$ crystals deposited due to evaporation.

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Solubility of sodium chloride solution at room temperature is 36g/100gof water. 200g of saturated solution of Sodium chloride was allowed to evaporate when 75g of water evaporated. Calculate the amount of crystals deposited due to evaporation.

Solubility of sodium chloride solution at room temperature is $36 g / 100 g$ of water. $200 g$ of saturated solution of Sodium chloride was allowed to evaporate when $75 g$ of water evaporated. Calculate the amount of crystals deposited due to evaporation.