Question

Solubility product constant $\left(K_{sp}\right)$ of salts of types $MX,M{X}_2$ and $M_{3}X$ at temperature $T$' are $4.0\times {10}^{-8},3.2\times {10}^{-14}$ and $2.7\times {10}^{-15}$, respectively. Solubilities (mole $d{m}^{-3}$) of the salts at temperature $T$' are in the order:

• A. $MX>M{X}_2>M_{3}X$
• B. $M_{3}X>M{X}_2>MX$
• C. $M{X}_2>M_{3}X>MX$
• D. $MX>M_{3}X>M{X}_2$

Answer 1

The correct option is D $MX>M_{3}X>M{X}_2$

From given solubility product,

Solubility of ($MX$) $=\sqrt{4\times {10}^{-8}}=2\times {10}^{-4}$

Solubility of $\left(M{X}_2\right)=8\times {10}^{-5}$

Solubility of $\left(M_{3}X\right)=1\times {10}^{-4}$

$\therefore MX>M_{3}X>M{X}_2$