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Question

Solubility product Ksp of a sparingly soluble salt Zn(CN)2 is 8×1012. Its solubility value in (mol L1) is:
(Take 32=1.26)

A
1.26×104
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B
1.26×105
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C
1.26×106
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D
1.26×1012
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Solution

The correct option is A 1.26×104
Given Ksp=8×1012
The equilibrium between the undissolved solid and the ions in a saturated solution can be represented by the equation: Zn(CN)2(s)Zn2+(aq)+2CN(aq)Initial: C 0 0Equilibrium: Cs s 2s

Ksp=[Zn2+][CN]2
Ksp=s×(2s)2=4s3
Ksp=4s3=8×1012
4s3=8×1012
s3=2×1012
s=1.26×104 M

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