Question

Solubility product of a salt AB is $1\times {10}^{-8}$ in a solution in which concentration of A is ${10}^{-3}$M. The salt will precipitate when the concentration of B becomes more than :

• A. ${10}^{-4}$
• B. ${10}^{-7}$
• C. ${10}^{-6}$
• D. ${10}^{-5}$

Answer 1

The correct option is D ${10}^{-5}$

Solubility product of a salt AB is $1\times {10}^{-8}$ in a solution in which concentration of A is $1\times {10}^{-3}$ M.

The salt will precipitate when the concentration of B becomes more than :

$\frac{Ksp}{\left[A\right]}=\frac{1\times {10}^{-8}}{1\times {10}^{-3}}=1\times {10}^{-5}$ M

Hence, the correct option is D.