Question

Solubility product of $AgCl$ is $1\times {10}^{-6}$ at $298K$. Its solubility in mole $litr{e}^{-1}$ would be____

• A. $1\times {10}^{-6}$ mole/ litre
• B. $1\times {10}^{-3}$ mole/ litre
• C. $1\times {10}^{-12}$ mole/ litre
• D. None of these

Answer 1

Answer: (B)

$1\times {10}^{-3}$ mole/ litre

For $AgCl\to \underset{x}{A{g}^{+}}+\underset{x}{C{l}^{-}}$

$K_{sp}=x^2;x=\sqrt{K_{sp}}=\sqrt{1\times {10}^{-6}}=1\times {10}^{-3}mol/litre$