Question

Solubility product of $CaC{O}_3$ is ${5\times 10}^{-9}$. Find its solubility.

Answer 1

$CaC{O}_3\to C{a}^{2+}+C{O}_3^{2–}$

The Solubility product of $CaC{O}_3$

$⟹K_{sp}=5\times {10}^{–9}$

If Solubility= s , then Solubility Product $=s^2=5\times {10}^{-9}.$

Therefore,

Solubility$=7.07\times {10}^{-5}\frac{mole}{L}$