Question

Solubility product of $CaC{O}_3$ is $5\times {10}^{-9}$, its solubility is :-

• A. $2.2\times {10}^{-9}$
• B. $7\times {10}^{-5}$
• C. $2.5\times {10}^{-4}$
• D. $2.5\times {10}^{-5}$

Answer 1

Answer: (B)

$7\times {10}^{-5}$

$CaC{O}_3\to C{a}^{+2}+C{O}_3^{-2}$

S S

$K_{sp}=\left[C{a}^{+2}\right]\left[C{O}_3^{-2}\right]=S^2=5\times {10}^{-9}$

$S=7.1\times {10}^{-5}$

So its solubility is $7\times {10}^{-5}$