Question

Solubility product of $CaC{O}_3$ is $5\times {10}^9$. Its solubility is:-

• A. $2.2\times {10}^{-9}$
• B. $7.07\times {10}^{-5}$
• C. $2.5\times {10}^{-4}$
• D. $2.5\times {10}^{-5}$

Answer 1

The correct option is B $7.07\times {10}^{-5}$

${CaCO}_3\rightleftharpoons {Ca}^{2+}\left(s\right)+{CO}_3^{2-}\left(s\right)$

If the solubility is $S$.

$\therefore$ $S^2=5\times {10}^{-9}\Rightarrow S=7.07\times {10}^{-5}$