Question

Solubility product of $CaC{O}_3$ is $5\times {10}^{-9}$.Its solubility is:-

• A. $2.2\times {10}^{-9}$
• B. $7\times {10}^{-5}$
• C. $2.5\times {10}^{-4}$
• D. $2.5\times {10}^{-5}$

Answer 1

The correct option is B $7\times {10}^{-5}$

Given,

solubility product $K_{sp}=$ $5\times {10}^{-9}$

$CaC{O}_3\to C{a}^{2+}+C{O_3}^{2-}$

Let $x$ - amount of each substance dissolved.

$K_{sp}-\left[C{a}^{2+}\right]\left[C{O_3}^{2-}\right]$

$5\times {10}^{-9}=\left[x\right]\left[x\right]$

$x^2=\sqrt{5\times {10}^{-9}}$

$x=7\times {10}^{-5}$

Hence, option B is the correct answer.