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Ways of Representing the Concentration of a Solution

Solubility pr...

Question

Solubility product of $M g (O H)_{2}$ is $9 \times 10^{- 12}$ . If concentration of $M g^{+ 2}$ in saturated solution is $0.01$ M, then concentration of $O H^{-}$ is?

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Solution

$M g (O H)_{2} ⇌ M g^{2 +} + 2 [O H]^{-}$
$\Rightarrow K_{s p} = [M g^{2 +}] [O H^{-}] 2$
Given, $K_{s p} = 9 \times 10^{- 12}$
$[M g^{2 +}] = 0.01 M$
$[O H^{-}] = \sqrt{\frac{K_{s p}}{[M g^{2 +}]}}$
$= \sqrt{\frac{9 \times 10^{- 12}}{10^{- 2}}}$
$∴ [O H^{-}] = 3 \times 10^{- 5}$ .

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