Solubility product of radium sulphate is 4 - 10-11mol2L-2- What will be the solubility of Ra2- in 0-10 M Na2SO4-

The correct option is D 2 × 10^ 10 M Na_2SO_4^2 → Na^+2+2SO_4^2 [SO^2 _4]=0.10× 2=0.20M Ra.SO_4→ #160; Ra^+2+SO_4^2 #160; #160; ...

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Byju's Answer

Standard XII

Chemistry

Solubility Product

Solubility pr...

Question

Solubility product of radium sulphate is $4 \times 10^{- 11} m o l^{2} L^{- 2}$ . What will be the solubility of $R a^{2 +}$ in $0.10$ M $N a_{2} S O_{4}$ ?

4 \times 10^{- 10}

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2 \times 10^{- 5}

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4 \times 10^{- 5}

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2 \times 10^{- 10}

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Solution

The correct option is D $2 \times 10^{- 10}$ M
$N a_{2} S O_{4}^{2 -} \to N a^{+ 2} + 2 S O_{4}^{2 -}$
$[S O_{4}^{2 -}] = 0.10 \times 2 = 0.20 M$
$R a . S O_{4} \to R a^{+ 2} + S O_{4}^{2 -}$
$¯ ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ ¯ 55$
$(s) (5 + 0.2) = 4 \times 10^{- 1}$
$5$ can be neglected in $(0.2 + 5)$
$5 \times \frac{0.2}{5} = \frac{4 \times 10^{- 11}}{\frac{}{}} = 2 \times 10^{- 10}$
Solubility of Rate is $2 \times 10^{- 10}$

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Solubility product of radium sulphate is 4×10−11mol2L−2. What will be the solubility of Ra2+ in 0.10 M Na2SO4?

The correct option is D 2×10−10MNa2SO2−4→Na+2+2SO2−4[SO2−4]=0.10×2=0.20MRa.SO4→Ra+2+SO2−4 ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯55(s)(5+0.2)=4×10−15 can be neglected in (0.2+5)5×0.25=4×10−11=2×10−10Solubility of Rate is 2×10−10

Solubility product of radium sulphate is $4 \times 10^{- 11} m o l^{2} L^{- 2}$ . What will be the solubility of $R a^{2 +}$ in $0.10$ M $N a_{2} S O_{4}$ ?