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Question

# Solubility products of Al(OH)3 and Zn(OH)2 are 2.7×10−23 and 3.2×10−14 respectively. If to a solution of 0.1 M each of Al3+ and Zn2+ions,NH4OH is added in increasing amounts which of the following will be precipitated first ?

A

Zn(OH)2

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B

Al(OH)3

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C

Both of them

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D

None of them

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Solution

## The correct option is B Al(OH)3 Al(OH)3(S)⇌Al3++3OH−;KSP=2.7×10−23=27S4⇒S=1.0×10−6M [OH−] required for precipitation of \)Al(OH)_3 = 3S = 3.0 \times 10^{-6}mol~L^{-1}\) Zn(OH)2(S)⇌Zn2+aq+2OH−(aq)KSP=3.2×10−14=4S3⇒S=2×10−5mol L−1 [OH]− required for precipitation of Zn(OH)2 =2S=4×10−5mol L−1

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