wiz-icon
MyQuestionIcon
MyQuestionIcon
13
You visited us 13 times! Enjoying our articles? Unlock Full Access!
Question

Solution A is a sodium hydroxide solution. Solution B is a weak acid. C is dilute sulphuric acid. Which solution will
(i) liberate sulphur dioxide from sodium sulphite,
(ii) give a white precipitate with zinc sulphate solution,
(iii) contain solute molecules and ions?

Open in App
Solution

(i) Solution C liberates sulphur dioxide from sodium sulphite. Sodium sulphite on reaction with dilute sulphuric acid produces sodium sulphate salt and liberates sulphur dioxide gas.
Na2SO3 + H2SO4 → Na2SO4 + H2O + SO2

(ii) Solution A gives a white precipitate with zinc sulphate solution. Sodium hydroxide reacts with zinc sulphate to form a white precipitate of zinc hydroxide.
ZnSO4 + 2NaOH → Zn(OH)2 + Na2SO4

(iii) Solution B contains both solute and water molecules because a weak acid ionises partially.

flag
Suggest Corrections
thumbs-up
13
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Carbonates
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon