Question

Solution for the system defined by the set of equations $4y+3z=8;2x-z=2$ and $3x+2y=5$ is

• A. $x=0,y=1,z=\frac{4}{3}$
• B. $x=0,y=\frac{1}{2},z=2$
• C. $x=1,y=\frac{1}{2},z=2$
• D. Non-existent

Answer 1

The correct option is D Non-existent

$4y+3z=8$ ....(i)
$2x-z=8$ ....(ii)
$3x+2y=5$ ....(iii)

Eliminating z from (i) & (ii)

$4y+3(2x-2)=8$
$\Rightarrow 3x+2y=7$ ....(iv)
(iii) & (iv) imply that the given system of equations is inconsistent.