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Question

Solution of differential equation secxdy−cosecydx=0 is

A
cosx+siny=c
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B
sinx+cosy=c
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C
sinycosx=c
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D
cosysinx=c
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Solution

The correct option is B sinx+cosy=c
secxdycosecydx=0
dycosx=dxsiny
By variable separable from
sinydy=cosxdx
integrating,
sinydy=cosxdx
cosy=sinx+c
sinx+cosy+c=0
or
sinx+cosy=c

1117080_460573_ans_ddc5ab14a5b8441a878145a0d1cb7ed7.JPG

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