Question

Solution of given simultaneous equation using Vedic maths is?
$7x+5y-3z=16$
$3x-5y+2z=-8$
$5x+3y-7z=0$

• A. $(1,3,2)$
• B. $(1,2,3)$
• C. $(2,3,1)$
• D. $(0,1,2)$

Answer 1

The correct option is A $(1,3,2)$

Given equations are $7x+5y-3z=16,3x-5y+2z=-8$ and $5x+3y-7z=0$.

Add the first two equations to get $10x-z=8$

Now multiplying the second equation by $3$ and the $3^{rd}$ equation by 5 and adding we have $34x-29z=-24.$

From our derived equation (1) and (2), we have

$256x=29\ast 8+24$ which implies $32x=32$ that is $x=1$

Substituting in our equation (1), we have $z=2$.

Substituting these values in any original equation, we get $y=3$.