CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solution of glucose (having molar mass 180 g/mol) is isotonic with 12 g of urea (having molar mass 60 g/mol) at a constant temperature. Both solutions are one litre each. Then the concentration of glucose is:

A
18 g/L
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
36 g/L
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
12 g/L
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
24 g/L
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 36 g/L
Osmotic pressure, π=CRT
Here C is concentration in molarity.
R is universal gas constant and T is temperature.
C=nV
n=Given massMolar mass
Given mass of urea=12 g
Volume of each solution =1 L
Since both solutions have same osmotic pressure, they have same concentrations also.
Let, the mass of glucose be X g per liter solution.
C1=C2
n1V=n2V1260=X180
X=36 g/L


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Osmotic Pressure
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon