Solution of ${log}_{(x^{2} + 6 x + 8)} ({log}_{(2 x^{2} + 2 x + 3)} (x^{2} - 2 x)) = 0$ is

a natural number.

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a negative number.

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- 1

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none of these

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Solution

The correct options are
B a negative number.
C $- 1$

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Similar questions

{log}_{x^{2} + 6 x + 8} {log}_{{2 x}^{2} + 2 x + 3} (x^{2} - 2 x) = 0

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{log}_{x^{2} - 6 x + 8} ({log}_{{2 x}^{2} - 2 x - 8} (x^{2} + 5 x)) = 0

Solution of $l o g_{x^{2} + 6 x + 8} l o g_{x^{2} + 2 x + 3} (x^{2} - 2 x) = 0 i s$

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