Solution of $N a_{2} C O_{3}$ in water will be

Acidic

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Neutral

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Basic

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Cannot be predicted

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Solution

The correct option is C Basic
$\begin{matrix} S i n c e, N a_{2} C o_{3} o s s a l t o f s t r o n g c a s e N a C l a n d w e a k a c i d H_{2} C O_{3} [N a x l + H_{2} C O_{3} \to N a_{2} C o_{3} + H C l] S o, O b v i o u s l y N a_{2} C o_{3} s o l^{n} i n w a t e r w i l l b e b a s i c i n n a t u r e H e n c e, t h e o p t i o n C i s t h e c o r r e c t a n s w e r . \end{matrix}$

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Similar questions

The salt which will give a neutral solution on dissolving in water will be :

(a) $C H_{3} C O O N a$

(b) $N H_{4} C l$

(d) $N a_{2} C O_{3}$

N a_{2} C O_{3}

N a_{2} C O_{3}

10^{- 2} M N a_{2} C O_{3}

(density of solution = 1.10 {g mL}^{- 1}

molecular weight of N a_{2} C O_{3} = 106 {g mol}^{- 1})

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