Question

Solution of sodium metals in liquid ammonia is strongly reducing due to the presence of:

• A. sodium hydride
• B. sodium atoms
• C. sodium amide
• D. solvated electrons

Answer 1

The correct option is D solvated electrons

The solution of sodium metals in liquid $N{H}_3$ is strongly reducing due to the presence of solvated electron which is a free electron.

$N{a}^{+}+(x+y)N{H}_3\to \left[Na\right(N{H}_3{)}_x{]}^{+}+\left[e\right(N{H}_3{)}_y{]}^{-}$

The solutions are a good conductor of electricity and have strong reducing properties.

Hence, the correct option is $D$