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Question

Solution of the differential equation 2xydydx=x2+3y2 is :
(where c is integration constant)

A
x3+y2=cx2
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B
x22+y32=y2+c
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C
x2+y2=|cx3|
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D
|x2y2|=cx3
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Solution

The correct option is C x2+y2=|cx3|
2xydydx=x2+3y2dydx=x2+3y22xy(i)
This is a homogeneous differential equation.

We put y=vx so that dydx=v+xdvdx

Equation (i) becomes:
v+xdvdx=x2+3v2x22vx2xdvdx=1+3v22vv2v1+v2dv=dxx
ln(1+v2)=ln|x|+ln|c|1+v2=|cx|x2+y2=|cx3|

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