CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solution of the differential equation (x2+y3)(2x2dx+3ydy)=12x dx+18y2dy is

A
23x3+32y2=6ln(x2+y3)+c
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
x2+y3=9ln(x2+y3)+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
23x3+32y2=6ln(x3+y2)+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
x3+y2=6ln(x2+y3)+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 23x3+32y2=6ln(x2+y3)+c
LHS(x2+y3)(2x2dx+3ydy)=2x4dx+3x2ydy+2x2y3dx+3y4dy2x4dx+3x2ydy+2x2y3dx+3y4dy=12xdx+18y2dy(or)thegivenquestioncanbewrittenas(2x2dx+3ydy)=6(2xdx+3y2dy)x2+y3integrating23x3+32y2=6ln(x2+y3)+C

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
General and Particular Solutions of a DE
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon