Solution of the inequality |3 - log2x| < 2 contains the interval.
x ∈ (2, 32)
|3 - log2x| < 2 - - - - - - (I)
By definition of logarithm x > 0
Since, |3 - log2x| < 2
⇒ 3 - log2x < 2 or 3 - log2x > -2
Common part of equation II and equation III is x ∈ (2, 32)
Correct option a.