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Question

Solution of the inequality |3 - log2x| < 2 contains the interval.


A

x (2, 32)

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B

x > 2

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C

x [2, 32]

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D

x < 32

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Solution

The correct option is A

x (2, 32)


|3 - log2x| < 2 - - - - - - (I)

By definition of logarithm x > 0

Since, |3 - log2x| < 2

3 - log2x < 2 or 3 - log2x > -2

Common part of equation II and equation III is x ∈ (2, 32)

Correct option a.


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