Solution of the inequality |3 - ${log}_{2} x$ | < 2 is ______.

3 - log₂x < 2

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3 - log₂ x > 2

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3 - log₂ x < -2

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3 - log₂ x > -2

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Solution

The correct options are
A
3 - log₂x < 2

D
3 - log₂ x > -2

|3 - ${log}_{2} x$ | < 2

In this inequality

3 - ${log}_{2} x$ < 2- - - - - - - (1)

Or

-3 - ${log}_{2} x$ < 2- - - - - - (2)

Multiply - 1 in equation 2

3 - ${log}_{2} x$ > -2

Suggest Corrections

Similar questions

{log}_{2} x \leq \frac{2}{{log}_{2} x - 1}

({log}_{2} x)^{2} - | ({log}_{2} x) - 2 | \geq 0

Solution of the inequality |3 - ${log}_{2} x$ | < 2 contains the interval.

{log}_{2 x + 3} x^{2} < {log}_{2 x + 3} (2 x + 3)

{log}_{2 x + 3} x^{2} < 1

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