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Question

Solution of yxdydx=5(y2+dydx), is:

A
(5+x)(15y)=cy
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B
5+x15y=cy
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C
(5x)(1+5y)=cy
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D
(5+x)(5x)=c
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Solution

The correct option is A (5+x)(15y)=cy
5y2y=dydx(5+x)

dx5+x=dyy(5y1)
dx5+x=5y(5y1)y(5y1)dy

Integrating both sides, we get
dx5+x=(515y+1y)dy

log(5+x)=log(15y)+logy+logc;(logc is a constant)

yc=(5+x)(15y)

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