Question

Solution set of $2x–1>7$ and $3x–2\le 16$ is

• A. $[4,6]$
• B. $(4,6)$
• C. $(4,6]$
• D. $[4,6)$

Answer 1

The correct option is C $(4,6]$

$2x–1>7$
$\Rightarrow 2x>8$
$\Rightarrow x>4$
$3x-2\le 16$
$\Rightarrow 3x\le 18$
$\Rightarrow x\le 6$
$\therefore x\in (4,6]$