Solution set of inequality $4 x + 3 < 5 x + 7$ is $(- 4, \infty)$ .

True

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

False

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A True
$4 x + 3 < 5 x + 7$
$4 x + 3 - 7 < 5 x + 7 - 7$
$4 x - 4 < 5 x$
$4 x - 4 - 4 x < 5 x - 4 x$
$- 4 < x$
Thus, the solution set of the given inequality is $(- 4, \infty)$ .

Suggest Corrections

Similar questions

The solution of inequality 4x + 3 < 5x + 7 when x is a real number is

5 (x - 2) > 4 (x + 3) - 24

- 4, - 3, - 2, - 1, 0, 1, 2, 3, 4 .

Solve the inequation,

3x - 4 < 2x + 1 ≤ 5x + 7, x ∈ R and graph the solution set.

2 (4 x - 1) \leq 3 (x + 4)

Join BYJU'S Learning Program