Solution set of log0.25(x2+2x−8)2−log0.5(10+3x+x2)=1
A
{−3}
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B
{14}
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C
{16(√313−1),12(√73−7)}
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D
{1,7}
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Solution
The correct option is C{16(√313−1),12(√73−7)}
log0.25(x2+2x−8)2−log0.5(10+3x+x2)=1 can be rewriten as log0.5|x2+2x−8|10+3x−x2=1⇒|x2+2x−8|10+3x−x2=12⇒2|x2+2x−8|=10+3x−x2⇒2|(x+4)(x−2)|=(5−x)(2+x)⇒x=16(√313−1),12(√73−7)