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Question

Solution set of log0.25(x2+2x8)2log0.5(10+3x+x2)=1


A
{3}
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B
{14}
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C
{16(3131),12(737)}
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D
{1, 7}
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Solution

The correct option is C {16(3131),12(737)}

log0.25(x2+2x8)2log0.5(10+3x+x2)=1 can be rewriten as
log0.5|x2+2x8|10+3xx2=1|x2+2x8|10+3xx2=122|x2+2x8|=10+3xx22|(x+4)(x2)|=(5x)(2+x)x=16(3131),12(737)


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