CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solution set of log0.25(x2+2x8)2log0.5(10+3x+x2)=1


A
{3}
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
{14}
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
{16(3131),12(737)}
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
{1, 7}
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C {16(3131),12(737)}

log0.25(x2+2x8)2log0.5(10+3x+x2)=1 can be rewriten as
log0.5|x2+2x8|10+3xx2=1|x2+2x8|10+3xx2=122|x2+2x8|=10+3xx22|(x+4)(x2)|=(5x)(2+x)x=16(3131),12(737)


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Modulus
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon