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Byju's Answer
Standard XII
Mathematics
Integration Using Substitution
Solution set ...
Question
Solution set of the inequality
1
2
x
−
1
>
1
1
−
2
x
−
1
is
A
(
1
,
∞
)
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B
(
0
,
log
2
(
4
/
3
)
)
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C
(
−
1
,
∞
)
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D
(
0
,
1
)
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Solution
The correct option is
B
(
0
,
log
2
(
4
/
3
)
)
1
2
x
−
1
>
1
1
−
2
x
2
1
2
x
−
1
−
1
1
−
2
x
2
>
0
l
e
t
2
x
=
t
1
t
−
1
−
2
2
−
t
>
0
1
t
−
1
+
2
t
−
2
>
0
t
−
2
+
2
t
−
2
(
t
−
1
)
(
t
−
2
)
>
0
(
t
−
4
3
)
(
t
−
1
)
(
t
−
2
)
>
0
t
ε
(
1
,
4
3
)
⋃
(
2
,
∞
)
2
x
ε
(
1
,
4
3
)
⋃
(
2
,
∞
)
x
log
2
2
ε
(
0
,
log
2
4
3
)
x
ε
(
0
,
log
2
4
3
)
Suggest Corrections
0
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