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Question

Solution set of the inequality 2cos2x1sinx2<0, can be.

A
(2n14)π<x<(2n+14)π, where n=1,3,6
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B
(n4)π<x<(n+14)π, where n=8
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C
(n14)π<x<(n4)π, where n=16
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D
(2n14)π<x<(2n+14)π, where n=5
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Solution

The correct option is A (2n14)π<x<(2n+14)π, where n=1,3,6
1826573_691650_ans_6ba7f944a9724093b30c6cb0dba2b5fe.jpeg

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