Question

Solution set of $(x+2)(x-7)<0$ is

• A. $-7<x<2$
• B. $-7<x<-2$
• C. $2<x<7$
• D. $-2<x<7$

Answer 1

The correct option is D $-2<x<7$

$(x+2)(x-7)<0$

Case -1
$x+2<0$ and $x-7>0$
$x<-2$ and $x>7$
It is not possible

Case -2
$x+2>0$ and $x-7<0$
$x>-2$ and $x<7$
So, the solution set is $-2<x<7$