Question

Solutions containing $23gHCOOH$ is/are :

• A. $46g$ of $70\%\left(\frac{w}{v}\right)HCOOH(d_{solution}=1.40g/mL)$
• B. $50g$ of $10MHCOOH(d_{solution}=1g/mL)$
• C. $50g$ of $25\%\left(\frac{w}{w}\right)HCOOH$
• D. $46g$ of $5MHCOOH(d_{solution}=1g/mL)$

Answer 1

Answer: (A), (B)

$50g$ of $10MHCOOH(d_{solution}=1g/mL)$
$46g$ of $70\%\left(\frac{w}{v}\right)HCOOH(d_{solution}=1.40g/mL)$

Mol. wt. of HCOOH is $46$.
Mass of HCOOH in $46g$ of $70\%\left(\frac{w}{v}\right)HCOOH(d_{solution}=1.40g/mL)$ is $=\left(46/1.4\right)\times 0.7=23$ gm.
Mass of HCOOH in $50g$ of $10MHCOOH(d_{solution}=1g/mL)$ is $=50\times 10\times 46/1000=23$gm.