Question

Solutions of silver nitrate and sodium chloride react to form a white precipitate of

• A. sodium chloride
• B. silver nitrate
• C. sodium nitrate
• D. silver chloride

Answer 1

The correct option is D

silver chloride

The explanation for the correct answer

(D) silver chloride

When silver nitrate and sodium chloride are reacted, Sodium being highly reactive displaces silver which is less reactive, and forms silver chloride(a white precipitate) and sodium nitrate. This reaction is an example of a double displacement reaction.

$\underset{\mathrm{Nitrate}}{\underset{\mathrm{Silver}}{{\mathrm{AgNO}}_3\left(\mathrm{aq}\right)}}+\underset{\mathrm{Chloride}}{\underset{\mathrm{Sodium}}{\mathrm{NaCl}\left(\mathrm{aq}\right)}}\to \underset{\mathrm{Chloride}}{\underset{\mathrm{Silver}}{\mathrm{AgCl}\left(\mathrm{s}\right)}}+\underset{\mathrm{Nitrate}}{\underset{\mathrm{Sodium}}{{\mathrm{NaNO}}_3\left(\mathrm{aq}\right)}}$

Therefore, the correct answer is an option (D) i.e, solutions of silver nitrate and sodium chloride react to form a white precipitate of silver chloride.