Solutions of sodium hydroixde and acetic acid are mixed:
Write the balanced chemical equation.

N a O H + C H_{3} C O O H \to C H_{3} C O O N a + H_{2} O

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N a O H_{2} + C H_{3} C O O H \to C H_{3} C O O N a + H_{2} O

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2 N a O H + C H_{3} C O O H \to C H_{3} C O O N a + H_{2} O

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N a O H + C H_{3} C O O H \to 3 C H_{3} C O O N a + H_{2} O

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Solution

The correct option is A $N a O H + C H_{3} C O O H \to C H_{3} C O O N a + H_{2} O$
When the sodium hydroxide reacts with an acetic acid, the NaOH, a base, it generates sodium acetate, a salt, and $H_{2} O$ .
$C H_{3} C O O H + N a O H \to C H_{3} C O O N a + H_{2} O$
Acid-base reaction always results in the salt of the acid and base and water.
Option $A$ is correct.

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What are the products of the reaction, $C H_{3} C O O H + N a_{2} C O_{3} \to$ ?

C H_{3} C O O H + N a O H ⟶ C H_{3} C O O N a + H_{2} O . . . . Δ H = - 13.2 K c a l

H^{\oplus} + ⊖ O H ⟶ H_{2} O; . . . . Δ H = - 13.7 K c a l

N H_{4} O H

H C l + N H_{4} O H ⟶ N H_{4} C l + H_{2} O; Δ H = - 12.27 K c a l

1 M

({C H}_{3} C O O N a)

+

({C H}_{3} C O O H + {C H}_{3} C O O N a)

({C H}_{3} C O O H)

$N a H C O_{3} + C H_{3} C O O H ⟶ C H_{3} C O O N a + C O_{2} + H_{2} O$ ,

This reaction is used as a test of carboxylic acid because :

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