Question

Solve

(1)

(2)

(3)

(4)

(5)

(6)

(7)

(8)

(9)

(10)

Answer 1

(1)

Cross multiplying the given equation, we get

Splitting the middle term, we get:

Hence, the roots of the quadratic equation are

(2)

Cross multiplying the given equation, we get:

Splitting the middle term, we get:

Hence, the roots of the quadratic equation are

(3)

Cross multiplying the given equation, we get:

Splitting the middle term, we get:

Hence, the roots of the quadratic equation are

(4)

Cross multiplying the given equation, we get:

Taking (5y + 6) common:

Hence, the roots of the quadratic equation are

(5)

Cross multiplying the equation above, we get:

Comparing the given equation with _,

Using the formula_:

Hence, the roots of the quadratic equation are

(6)

Cross multiplying the equation above, we get:

Here, 13 × 116 = 26 × 58

Splitting the middle term, we get:

Hence, the roots of the quadratic equation are

(7)

Cross multiplying the equation above, we get:

Splitting the middle term, we get:

Hence, the roots of the quadratic equation are

(8)

Cross multiplying the equation above, we get:

Splitting the middle term, we get:

Hence, the roots of the quadratic equation are _.

(9)

Cross multiplying the equation above, we get:

Splitting the middle term, we get:

Hence, the roots of the quadratic equation are

(10)

Cross multiplying the equation above, we get:

Splitting the middle term, we get:

Hence, the roots of the quadratic equation are