Question

Solve $1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+\dots \infty$

Answer 1

$log(1+x)=x-\left(\frac{x^2}{2}\right)+\left(\frac{x^3}{3}\right)-\left(\frac{x^4}{4}\right)+........\infty putx=1,wegetlog(1+1)=1-\left(\frac{1}{2}\right)+\left(\frac{1}{3}\right)-\left(\frac{1}{4}\right)+......\infty =log2$