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Byju's Answer
Standard VI
Mathematics
Divisibility Tests for 8
Solve: 1 15...
Question
Solve:
1
1
5
×
[
(
6
1
3
−
3
2
5
)
÷
4
2
4
]
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Solution
1
1
5
×
[
(
6
1
3
−
3
2
3
)
÷
4
2
4
]
⇒
1
×
5
+
1
5
[
(
18
+
1
3
−
3
×
3
+
2
3
)
÷
4
×
2
+
1
2
]
⇒
6
5
[
(
19
3
−
11
3
)
÷
9
2
]
⇒
6
5
(
8
3
÷
9
2
)
⇒
6
5
×
8
3
×
2
9
=
32
45
.
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0
Similar questions
Q.
Look at the figures and write or '>','<', '=' between the given pairs of fractions.
(a)
1
6
□
1
3
(b)
3
4
□
2
6
(c)
2
3
□
2
4
(d)
6
6
□
3
3
(e)
5
6
□
5
5
Q.
Find the missing number.
5
6
12
42
7
5
7
42
3
4
10
22
5
?
12
32
Q.
solve:
(i)
6
1
4
÷
1
1
3
(ii)
12
÷
1
3
4
(iii)
1
3
×
2
1
3
Q.
50
×
5
÷
2
+
24
140
÷
[
(
−
11
)
×
(
−
3
)
−
(
−
42
)
÷
14
−
3
5
+
3
8
÷
6
4
Q.
State TRUE or FALSE.
(
32
)
−
2
5
÷
(
125
)
−
2
3
is equal to
6
1
4
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