Solve- 1-sin2A1-cos A-cos A

Taking LHS, 1 sin^2A1+cos A =cos A+ cos^2 A1+ cos A = cos A(1+ cos A)1+ cos A = cos A = RHS #160; #160; #160; #160; #160; ...

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Integrating Factor

Solve: 1-sin...

Question

Solve:
$1 - \frac{{sin}^{2} A}{1 + cos A} = cos A$

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Solution

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$\frac{s i n 2 A}{1 + c o s 2 A}$ . $\frac{c o s A}{1 + c o s A}$ =

\frac{cos A}{1 - tan A} - \frac{{sin}^{2} A}{cos A - sin A} = sin A + cos A

\frac{1 + cos A}{{sin}^{2} A} = \frac{1}{1 - cos A}

Prove the following trigonometric identities:\

$\frac{1 + c o s A}{s i n^{2} A} = \frac{1}{1 - c o s A}$

(sec A + cos A) (sec A - cos A) = {tan}^{2} A + {sin}^{2} A

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